Respuesta :

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6x + 3y = 9
2x + 3y = 1

Subtract the equations from each other.

4x = 8

Divide both sides by 4.

x = 2

Plug in (2) for x in the first equation.

6x + 3y = 9

6(2) + 3y = 9

12 + 3y = 9

Subtract 12 from both sides.

3y = (9-12)

3y = -3

Divide both sides by 3.

y = -1

(2, -1)

~Hope I helped!~
Solution 1: 6(x) + 3(y) = 9
Solution 2: 2(x) + 3(y) = 1
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Your graphic organizer↓
3(y) + 6(x) = 9
3(y) + 2(y)= 1 
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For the y-intercept; solution 2 ↓
"2" becomes a negative
3(y) which is equal to -2(x) + 1 
Take off the "3" then this becomes y = [tex] \frac{-2(x)}{3} [/tex] + [tex] \frac{1}{3} [/tex]
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Moving on to the x-intercept ; the first solution 
6(x) + 3 [tex]( \frac{-2(x)}{3} ) + \frac{1}{9} [/tex] = 9
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We can simplify to find the x-intercept
4(x) = 8 
the x-intercept is 2
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Lastly, we are looking for the y-intercept
[tex] \frac{-2(x) }{3} + \frac{1}{3} = ? [/tex]
 [tex] -\frac{2}{3} (2) + \frac{1}{3} = -1 [/tex]
 
So, the y-intercept is: -1 
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Answer↓
[tex] \left \{ {{x=2} \atop {y=-1}} \right. [/tex]

x-intercept: 2

y-intercept: -1 

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