Respuesta :

msm555

Answer:

101.8 unit sqaure

Step-by-step explanation:

Solution Given:

no of side(n)=8

radius(r)=6

Area =?

we have

[tex]\boxed{\bold{Area\: of \:regular\: polygon =nr^2sin(\frac{180}{n})Cos(\frac{180}{n})}}[/tex]

where

r is the radius and n is no of the side.

Now

Substituting Value:

[tex]Area\: of \:regular\: polygon =8*6^2sin(\frac{180}{8})Cos(\frac{180}{8})\\=8*36*0.38268*0.923879\\=101.823[/tex]

in nearest tenth 101.8 unit square

Answer:

101.8 square units

Step-by-step explanation:

The given diagram shows a regular octagon with a radius of 6 units.

The radius of a regular polygon is the distance from the center of the polygon to one of its vertices.

Therefore:

  • Number of sides: n = 8
  • Radius: r = 6

To find the area of a regular polygon given its radius and number of sides, we can use the following formula:

[tex]\boxed{\begin{minipage}{5.5cm}\underline{Area of a regular polygon}\\\\$A=nr^2\sin \left(\dfrac{180^{\circ}}{n}\right)\cos\left(\dfrac{180^{\circ}}{n}\right)$\\\\\\where:\\\phantom{ww}$\bullet$ $n$ is the number of sides.\\ \phantom{ww}$\bullet$ $r$ is the radius.\\\end{minipage}}[/tex]

Substitute n = 8 and r = 6 into the formula and solve for A:

[tex]A=8\cdot 6^2\sin \left(\dfrac{180^{\circ}}{8}\right)\cos\left(\dfrac{180^{\circ}}{8}\right)[/tex]

[tex]A=288\sin \left(22.5^{\circ}\right)\cos\left(22.5^{\circ}\right)[/tex]

[tex]A=101.823376...[/tex]

[tex]A=101.8\; \sf square\;units\;(nearest\;tenth)[/tex]

Therefore, the area of a regular octagon with a radius of 6 units is 101.8 square units, to the nearest tenth.

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