Question

How many moles of glucose (C6H12O6) are in 4.0 liters of a 4.5 M C6H12O6 solution?

Answer 1

molarity is the ratio of the moles of the solute over the volume of the solution in liters. In this case, we are given with 4.5 M or 4.5 mol/L which when multiplied by 4 liters of solution, the moles of glucose contained in the solution is equal to 18.0 moles of glucose.

Answer 2

Answer: 18 moles

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n= moles of solute  = ?

 $V_s$ = volume of solution in L = 4.0 L

Putting in the given values:

$4.5M=\frac{n}{4L}$

$n=18moles$

Thus 18 moles of glucose are present in 4.0 L of 4.5 M glucose solution.