Question

What's the slope-intercept form of the equation of the line graphed in this figure?

A) y = –3∕5x + 1

B) y = –5∕ x – 1

C) y = 5∕3x + 1

D) y = 3∕5x + 1

Answer 1

Answer:

Option D

Step-by-step explanation:

Slope intercept form:

       (-5, -2)   ;   x₁ = -5  & y₁ = -2

        (5 , 4)    ;   x₂ = 5   & y₂ = 4

Plugin the points in the below mentioned formula and find the slope.

  $\boxed{\bf slope =\dfrac{y_2-y_1}{x_2-x_1}}$

             $\sf = \dfrac{4-[-2]}{5-[-5]}\\\\\\=\dfrac{4+2}{5+5}\\\\=\dfrac{6}{10}\\\\=\dfrac{3}{5}$

Equation of slope-intercept form: y =mx + b

Here, m is the slope and b is the y-intercept.

     $\sf y = \dfrac{3}{5}x + b$

  The line is passing through (5, 4). So, substitute the points in the equation and find the y-intercept.

           $4 =\dfrac{3}{5}*5 + b\\\\\\4=3+b$

      4 - 3 = b

            b = 1

Slope intercept form of the equation:

            $\sf y = \dfrac{3}{5}x + 1$