Question

which compounds are the Bronsted- Lowry bases in the equilibrium?
HC2O4- + H2BO3- <=> H3BO3 + C2O4 2-?

A. H2BO3- and H3BO3
B. HC2O4- and H3BO3
C. HC2O4- and C2O4 ^2-
D. H2BO3- and C2O4 ^2-
E. HC2O4- and H2 BO3-

Answer 1

its D for plato. 
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Answer 2

Answer : Option D) $H_{2}BO_{3}^{-} and C_{2}O_{4}^{2-}$.

Explanation : The acid base theory of Bronsted-Lowry, stated the definition of acids and bases on the basis of conjugated.

The fundamental concept of this theory states that when an acid and a base reacts with each other, the acid forms its conjugate base, and the base forms its conjugate acid by exchanging the proton.

So, in the given reaction;

$HC_{2}O_{4}^{-} + H_{2}BO_{3}^{-} <---> H_{3}BO_{3} + C_{2}O_{4}^{2-}$

It is firstly observed that the species $H_{2}BO_{3}^{-}$ is accepting a proton from the acid, therefore this is one of the bases.

Secondly,$C_{2}O_{4}^{2-}$ accepts the proton and forms the reactant again in the reversible reaction.

Therefore, these are the correct options.

$H_{2}BO_{3}^{-} and C_{2}O_{4}^{2-}$