Respuesta :
Answer:
Step-by-step explanation:
We have to prove that the diagonals of parallelogram bisect each other.
Consider, ABCD is a parallelogram with AC and BD as diagonals and M is the point of intersection of the two diagonals.
We have to prove that MA=MC and MB=MD.
Now, In ΔAMD and ΔBMC, we have
∠MAD=∠MCB (Alternate angles as ABCD is parallelogram and DC║AB)
AD=BC (Opposite sides of parallelogram)
∠ADM=∠MBC (Alternate angles as ABCD is parallelogram and DC║AB)
Thus, by SAS rule of congruency,
ΔAMD ≅ ΔBMC
⇒MA=MC and MB=MD (CPCT)
Therefore, we use the method of congruent triangles in order to prove that diagonals of parallelogram bisect each other.
Hence, option A is correct.

The concept of congruent triangles can be used to show that the diagonals of a parallelogram bisect each other.
A diagonal is a line that divides a quadrilateral into two equal parts. This gives us two triangles. We know that a parallelogram is a quadrilateral because it has four sides.
If we make a diagonal in a parallelogram, we now have two congruent triangles. we can now use the concept of congruent triangles to show that the diagonals of a parallelogram bisect each other.
Learn more about a parallelogram: https://brainly.com/question/1563728