Question

Donnie is solving the equation 2x^2=27+3x with the quadratic formula. What values should he use for a , b , and c? A. a=2 b=27 c=3 B. a=2 b=-27 c=-3 C. a=2 b=3 c=27 D. a=2 b=-3 c=-27

Answer 1

Answer:

The value of a,b and c is:

              $a=2,\ b=-3\ \text{and}\ c=-27$

Step-by-step explanation:

We know that any quadratic equation is given by the form:

                     $ax^2+bx+c=0$

and the formula which gives the solution of the equation is given by:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here we have the equation as:

        $2x^2=27+3x$

which is also given by:

$2x^2-(27+3x)=0\\\\i.e.\\\\2x^2-27-3x\\\\2x^2-3x-27=0$

i.e. on comparing with the general quadratic formula we have:

$a=2,\ b=-3\ and\ c=-27$

Answer 2

Answer:

The answer is C i took the test

Step-by-step explanation: