Question

What is x2 – 6 = 16x + 30 rewritten in standard form, then factored? What value(s) of x make the equation true?

Answer 1

Answer:

The answer would be (x+2)(x-18)=0

the values that make it true are x=-2 and x=18

Step-by-step explanation:

Answer 2

The standard form of the parabola is x^2 - 16x - 36 = 0, and the factorized form is y = 1*(x - 18)*(x + 2)

How to write the parabola in standard form?

To do it, we just move all the terms to one side of the equation. We start with:

x^2 - 6 = 16x + 30

Now we can move all the terms to the left to get:

x^2 - 6 - 16x - 30 = 0

x^2 - 16x - 36 = 0

This is the standard form.

Now we solve the equation, we will use Bhaskara's formula, the solutions are:

$x = \frac{-(-16) \pm \sqrt{(-16)^2 - 4*1*(-36)} }{2} \\\\x = \frac{16 \pm 20 }{2}$

Then the two solutions are:

x = (16 + 20)/2 = 18

x = (16 - 20)/2 = -2

And the factorized form for a parabola with solutions x₁ and x₂ and a leading coefficient a is:

y = a*(x - x₁)*(x - x₂)

Then in our case, the factorized form is:

y = 1*(x - 18)*(x + 2)

If you want to learn more about parabolas, you can read:

https://brainly.com/question/1480401