Respuesta :

well i think the answer is [tex] 10^{-6} [/tex]
bcalle
(1.08 x 10^-3) * (9.3x10^-3) = 10.044 x 10^-6
.01 = 10x10^-2

10.044 x 10^-6
--------------------- = 1.0044 x 10^-4
10 x 10^-2
RELAXING NOICE
Relax