Respuesta :

Let [tex]g(x)=ax^2+bx+c[/tex]. Then

[tex]\begin{cases}g(0)=c\\g'(0)=b\\g''(0)=2a\end{cases}[/tex]

Meanwhile, since [tex]f(x)=e^x[/tex], you have [tex]f(0)=f'(0)=f''(0)=e^0=1[/tex].

It follows that [tex]a=\dfrac12[/tex], [tex]b=1[/tex], and [tex]c=1[/tex], so that the quadratic fit for [tex]f(x)=e^x[/tex] that satisfies the given points is

[tex]g(x)=\dfrac12x^2+x+1[/tex]

Note that this is just the second-order Taylor polynomial for [tex]e^x[/tex] about [tex]x=0[/tex].
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