Answer:
School A: 850 + 45t
School B: 1000 + 35t
After 15 years, both school has same strength and the total students in both school is 1525.
Step-by-step explanation:
High school A:
Current strength = 850 students.
New admission of students each year = 45 students
New admission of students in 't' years = 45*t = 45t
To find the total students after 't' years, add the current strength with 45t.
Total strength of the school A after 't' years = 850 + 45t
High school B:
Current strength = 1000 students.
New admission of students each year = 35 students
New admission of students in 't' years = 35*t = 35t
To find the total students after 't' years, add the current strength with 35t.
Total strength of the school B after 't' years = 850 + 35t
It is given that, the number of students are same in both schools after 't' years.
Strength of School A = Strength of School B
850 + 45t = 1000 + 35t
45t = 1000 + 35t - 850
45t = 1000 - 850 + 35t
45t = 150 + 35t
45t - 35t = 150
10t = 150
t = 150 ÷ 10
t = 15
Strength of School A = 850 + 45 *15
= 850 + 675
= 1525
Strenght of school B = 1000 + 35*15
= 1000 + 525
= 1525