Question

The areas of two similar octagons are 112 in.2 and 63 in.2. What is the ratio (larger to smaller) of their perimeters?

Answer 1

might be late but since the area is a squared unit (m^2), it's 2-dimensional perimeter is just a plain unit(m), it's 1-dimensional the 2-dimensional ratio is 112/63 Then, the 1-dimensional ratio is sqrt(112/63), which is 4/3. Plus i just took the quiz and got that question right :)

Answer 2

The ratio of the perimeter of the similar octagons is: 4/3.

What is the Areas of Two Similar Shapes?

If shape A has a side of a, and shape B has a corresponding side of b, and both shapes are similar, we will have the following:

Area of shape A/area of shape B = a²/b².

The ratio of their perimeter would therefore be expressed as: a/b.

Given that two octagons that are similar have areas of 112 in.² and 63 in.² respectively, therefore:

112/63 = a²/b²

16/9 = a²/b²

Square both sides to find the values of a/b

√(16/9) = a/b

4/3 = a/b

Therefore, the ratio of the perimeter of the similar octagons is: 4/3.

Learn more about areas of similar shapes on:

https://brainly.com/question/12580764