Use the question marck Moles of CO2 The the giving = 0.624 mol O2 Find the CF faction = 1 mole= 32.00 of O2
O= 2x16.00= 32.00amu ( writte this in the cf fraction) SET UP THE CHART Always start with the giving
0.624 mol O2 / 1mol of CO2 ___________ / _____________ = Cancel the queal ( O2) / 32.00c O2 / / Multiply the top and divide by the bottom 0.624 mol CO x 1mol CO2 = 0.624 divide by 32.00 O2 =0.0195 You should look at the giving number ( how many num u gor ever there) Ur answer should have the same # as ur givin so = 0.0195 = .0195 mol of CO2