How much heat was absorbed or lost by the surroundings? use 4.184 j/goc for the specific heat of the solution. put your answer in units of kj and make sure the sign is correct?

Respuesta :

to solve the amount heat that was added or lost in the surrounding, use the formula:
q = m cp dt
where q is the heat
m is the mass of the substance
cp is the specific heat of the subtance
dt is the change in temperature ( t2 - t1 )
just substitute the given value
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