Question

How many g i2 should be added to 750g ccl4 to prepare a 0.200m solution?

Answer 1

Answer:

Mass of I2 required = 38.1 g

Explanation:

Given:

Mass of CCl4 = 750 g = 0.750 kg

Molality of the solution = 0.200 m

To determine:

Mass of I2

Formula:

Molality of a solution is expressed as the ratio of the amount of solute per kg of solvent

$Molality = \frac{moles\ of\ solute}{kg\ solvent}$

Here the solute is I2 and solvent is CCl4

$Moles\ of\ I2 = molality*mass\ solvent = 0.200*0.750= 0.150 moles\\\\Molar\  mass\  of\  I2 = 253.8 g/mol\\\\Mass\ of\ I2 = moles*molar\ mass = 0.150*253.8 = 38.1 g$

Answer 2

Based on molality, 38.1 g of I₂ should be added to 750g CCl₄ to prepare a 0.200 m solution.

How many g I₂ should be added to 750g ccl4 to prepare a 0.200 m solution?

Concentration of solution expressed in moles of solute and mass of solvent is known as molality.

• Molality = moles of solute/mass of solvent in kg

In the given solution, the solvent is CCl₄ and the solute is I₂

Molailty of solution = 0.200

mass of solvent = 750 g or 0.75 kg

To determine the mole of solute required, the formula below is used:

• moles of solute = molality * mass of solvent in kg

moles of solute = 0.15 moles of I₂

mass of I₂ = moles * molar mass

molar mass of I₂ = 254 g/mol

mass of I₂ = 254 * 0.15

mass of I₂ = 38.1 g

Therefore, 38.1 g of I₂ should be added to 750g CCl₄ to prepare a 0.200 m solution.

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