Question

Find the zeros. g(x)=(x^2+4x-12)(x-3)

Answer 1

g(x)=(x^2+4x-12)(x-3)
=(x+6)(x-2)(x-3)
=x+6 = 0
-6 -6
x=-6

x-2 = 0
+2 +2
x=2

x-3 = 0
+3 +3
x=3
The zeros are {-6, 2, 3}