maggie43
maggie43
03-03-2017
Chemistry
contestada
A solution with pH of 9 has [OH-] concentration of
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TSO
TSO
10-03-2017
pH = -log([H+])
[H+] = 10^(-pH)
[H+] = 10^(-9)
[H+][OH-] = Kw
Kw = 1.0*10^-14 at 25 degrees celsius.
[OH-] = Kw/[H+] = (1.0*10^-14)/(1*10^-9) = 1.0*10^-5
The concentration of OH- ions is
1.0*10^-5 M
.
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