Question

if the perimeter of the rectangle is 32cm and the area is 55cm2, what are the dimensions of the rectangle?

Answer 1

2L + 2W = 32
L * W = 55

L = 55/W then substitute into first equation
2 * 55/W + 2W = 32 Multiplying both sides by "W"
110 + 2W^2 = 32 W
2W^2 -32W +110 = 0
L = 11 or L = 5
Also W = 11 or W = 5