The chemical reaction for this is expressed as:
4FeCO3 + 4O2 ----> 4FeO3 + 4CO2
We are first need to calculate the theoretical amount of ferric oxide that whould be obtain from the given amount of ore. We do as follows:
75 g FeCO3 ( 1 mol / 116 g ) ( 4 mol FeO3 / 4 mol FeCO3 ) ( 103.84 g / mol ) = 67.14 g FeO3 theoretically produced
Percent yield = actual mass / theoretical mass x 100 = 45 / 67.14 x 100 = 67.03%
