Given the function f(x) = 8x +5, evaluate and simplify the expressions below. See special instructions on how to enter your answers. Look at photo for the expressions and special instructions
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Answer:
[tex]f(a)=8a+5\\\\f(x+h)=8x+8h+5\\\\\frac{f(x+h)-f(x)}{h}=8[/tex]
Step-by-step explanation:
When we're asked to write what f(x+h) or f(a) is equal to, all we really have to do is substitution. The original function is provided as [tex]f(x)=8x+5[/tex], and all that "x" represents is input, now we can manipulate what that input is by simply substituting in new input. So if we want to write f(x+h), we substitute in "x+h" for "x".
For this problem, we just do what was stated about and replace all of the x's, with a's, meaning: [tex]8x+5\to 8a+5[/tex].
We essentially do the same thing here, although we will have to simplify more, but the first step is as follows: [tex]8x+5\to 8(x+h)+5[/tex], now from here we want to expand out the [tex]8(x+h)[/tex] by using the distributive property, so it becomes: [tex]8x+8h[/tex] and plugging this into our equation we get: [tex]8x+8h+5[/tex]
For this last question, I think it's also important to note that this is the formula to calculate the slope between point "x" and the point "h units away" or "x+h".
We already know what f(x+h) is and what f(x) is, so let's plug those into the equation:
[tex]\frac{(8x+8h+5)-(8x+5)}{h}[/tex]
Now let's distribute the negative sign to get:
[tex]\frac{8x+8h+5-8x-5}{h}[/tex]
Now let's group like terms:
[tex]\frac{(8x-8x)+(5-5)+8h}{h}[/tex]
Now let's simplify the grouped terms
[tex]\frac{8h}{h}[/tex]
Now let's divide by h to get:
[tex]8[/tex]
And this is our answer!