Question

A well insulated and perfectly sealed room is installed with 4 HP fan to circulate air for 1.5 hours. Determine the increase in internal energy of the air answer is 1.61 x10^7 J

Answer 1

"Increase in internal energy = energy consumed by fan " as the room is perfectly insulated and sealed.

energy consumed by fan = power x time
power of fan = 4HP = 4 x 745.7 W = 2982.8 W
time = 1.5 hours = 1.5 x 60 x 60 = 5400 s

 energy consumed by fan = 2982.8 x 5400 = 16107120 J = 1.61x10^7 J

Increase in internal energy is 1.61x10^7 J

Answer 2

The increase in internal energy will be "1.61×10⁷ J".

Given:

Power,

• $P = 4 \ HP$

or,

           $= 4\times 745.7$

           $= 2982.8 \ W$

Time,

• $T = 1.5 \ hours$

or,

           $= 1.5\times 60\times 60$

           $= 5400 \ s$    

Now,

The increase in the internal energy:

= $Power\times Time$

= $2982.8\times 5400$

= $1.61\times 10^7 \ J$

Thus the response above is right.

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