Question

6 pints of a 20 percent solution of alcohol in water are mixed with 4 pints of a 10 percent alcohol in water solution. The percentage alcohol in the new solution is

A. 16
B. 15
C. 14
D. 13
E. 12
am I correct by saying 15?

Answer 1

Total Volume would be 6 + 4 = 10 pints
Let's calculate the volume of alcohol in final solution:
20% * 6 = 1.2 pints
10% * 4 = .4 pints
Total = 1.6 pints of alcohol in 10
Percentage = (1.6/10) * 100 = 16 per cent.
answer is A

Answer 2

The percentage alcohol in the new solution is : 16%(A)

Further explanation

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. Concentration shows the amount of solute in a unit of the amount of solvent.

Molarity (M)

Molarity shows the number of moles of solute in every 1 liter of solution.

$\large {\boxed {\bold {M ~ = ~ \frac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = volume of the solution

MIXING SOLUTIONS

Molarity of the mixture of 2 solutions:

Vm Mm = V1. M1 + V2. M2

so that:

$\displaystyle Mm =\frac{V1.M1+V2.M2}{Vm}$

where :

Mm = Mixed molarity (M)

Vm = V1 + V2 = mixed volume (ml)

6 pints of a 20 percent solution of alcohol in water are mixed with 4 pints of a 10 percent alcohol in water solution.

V1=6 pints = 2.83906 liters, and concentration M1 =20% = 0.2

V2=4 pints = 1.89271 liters, M2=10% = 0.1

Vm = 2.83906 + 1.89271 = 4.73177 Liters

$\displaystyle Mm=\frac{V1.M1+V2.M2}{Vc}\\\\Mm=\frac{2.83906.0.2+1.89271.0.1}{4.73177}\\\\Mm=0.16=16\%$

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Keywords: molarity, alcohol solution,mixed solution,pints