Answer:
3 -√7
Step-by-step explanation:
You want to rationalize the denominator of 2/(3 +√7).
The denominator of such an expression is turned to an integer by multiplying numerator and denominator by the conjugate of the denominator.
[tex]\dfrac{2}{3+\sqrt{7}}=\dfrac{2}{3+\sqrt{7}}\cdot\dfrac{3-\sqrt{7}}{3-\sqrt{7}}=\dfrac{2(3-\sqrt{7})}{3^2-7}=\boxed{3-\sqrt{7}}[/tex]
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Additional comment
This process takes advantage of the factorization of the difference of squares:
a² -b² = (a +b)(a -b)
If 'b' is a value that can be made a rational real number by squaring it, then this multiplication by the conjugate can achieve that end. The conjugate of a sum is the corresponding difference.
This process is also used with complex numbers, since i² = -1, a real number.