please help 100 points wrong answers and links will be reported
Circle and Show!
(4 points each: 1 for the correct answer and 3 for supporting work!)
For numbers 8 -12, check the box next to the correct answer and type your work for that
problem.
Work must support your answer selection for credit!

please help 100 points wrong answers and links will be reported Circle and Show 4 points each 1 for the correct answer and 3 for supporting work For numbers 8 1 class=
please help 100 points wrong answers and links will be reported Circle and Show 4 points each 1 for the correct answer and 3 for supporting work For numbers 8 1 class=

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Please find attached herewith the solutions of your questions.

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Ver imagen Limelight15
Ver imagen Limelight15

Answer:

[tex]\textsf{8.} \quad \textsf{B.}\;8x^3y[/tex]

[tex]\textsf{9.} \quad \textsf{D.}\;81x^8[/tex]

[tex]\textsf{10.} \quad \textsf{A.}\;10t^{-7}[/tex]

[tex]\textsf{11.} \quad \textsf{C.}\;\dfrac{3m^2}{x^3}[/tex]

[tex]\textsf{12.} \quad \textsf{B.}\;\dfrac{1}{3m^9}[/tex]

Step-by-step explanation:

Exponent Rules

[tex]\textsf{Product rule}: \quad a^b \cdot a^c=a^{b+c}[/tex]

[tex]\textsf{Power rule}: \quad (a^b)^c=a^{bc}[/tex]

[tex]\textsf{Quotient rule} \quad \dfrac{a^b}{a^c}=a^{b-c}[/tex]

[tex]\textsf{Power of a Product rule}: \quad (ab)^c=a^{c} \cdot b^c[/tex]

[tex]\textsf{Negative exponent rule} \quad a^{-n}=\dfrac{1}{a^n}[/tex]

Question 8

[tex]\begin{aligned}\left(2x^2y^3\right)\left(4xy^{-2}\right)&=2 \cdot 4 \cdot x^2 \cdot x \cdot y^3 \cdot y^{-2}\\&=8\cdot x^{(2+1)}\cdot y^{(3-2)}\\&=8 \cdot x^3 \cdot y^1\\&=8x^3y\end{aligned}[/tex]

Question 9

[tex]\begin{aligned}\left(3x^2\right)^4&=3^4 \cdot (x^2)^4\\&=81 \cdot x^{(2 \cdot 4)}\\&=81x^8\end{aligned}[/tex]

Question 10

[tex]\begin{aligned}5t^{-2} \cdot 2t^{-5}&=5 \cdot 2 \cdot t^{-2} \cdot t^{-5}\\&=10 \cdot t^{(-2-5)}\\&=10t^{-7}\end{aligned}[/tex]

Question 11

[tex]\begin{aligned}\dfrac{6m^{10}x^4}{2m^8x^7}&=\dfrac{6}{2} \cdot \dfrac{m^{10}}{m^8} \cdot \dfrac{x^4}{x^7}\\\\&=3 \cdot m^{(10-8)} \cdot x^{(4-7)}\\\\&=3m^2x^{-3}\\\\&=\dfrac{3m^2}{x^3}\end{aligned}[/tex]

Question 12

[tex]\begin{aligned}\dfrac{m^{-3}}{3m^6}&=\dfrac{1}{3} \cdot \dfrac{m^{-3}}{m^{6}}\\\\&=\dfrac{1}{3} \cdot m^{(-3-6)}\\\\&=\dfrac{1}{3} \cdot m^{-9}\\\\&=\dfrac{1}{3m^9}\end{aligned}[/tex]

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