Question

A balloon containing 0.10 moles of gas has a volume of 2.0 liters. If temperature and pressure remain constant, what will be the new volume when 0.40 moles of gas are added to the balloon?
0.50 L
1.0 L
6.0 L
8.0 L

Answer 1

use n1/V1 = n2/V2

.1/2 = .4/V2
.1V2 = .8
V2 = 8 L or D

Answer 2

Answer:The new volume when 0.40 moles of gas are added to the balloon is 8 L.

Explanation:

Initial moles of gas $n_1$ = 0.10 moles

initial volume of the balloon, $V_1$ = 2.0 L

Final moles of gas $n_2$ = 0.40 moles

Final volume of the balloon, $V_2$ = 2.0 L

Avogadro Law:$\frac{n_1}{V_1}=\frac{n_2}{V_2}$

$V_2=\frac{n_2\times V_1}{n_1}=\frac{0.40 mol\times 2.0L}{0.10 mol}=8.0 L$

The new volume when 0.40 moles of gas are added to the balloon is 8 L.