Respuesta :
1st find mol of Al = 58/27 = 2.148 mol
There is a 1:1 ratio between AlCl3 and Al so 2.148 mol should be produced
take 2.148 * 133.5 = 286.75 g should be produced
% yield = 203/286.75 = .707 = 71% or C
There is a 1:1 ratio between AlCl3 and Al so 2.148 mol should be produced
take 2.148 * 133.5 = 286.75 g should be produced
% yield = 203/286.75 = .707 = 71% or C
Answer:
70.82%
Explanation:
Recall that: mole = mass/molar mass
From the equation of the reaction; [tex]2Al + 3 Cl_2 --> 2AlCl_3[/tex]
2 moles of aluminium gives 2 moles of AlCl3
58/26.98 moles of aluminium will give x/133.34 moles of AlCl3
x = 2.1497 x 133.34
= 286.64 g
58 grams of aluminium is supposed to yield 286.64 grams of aluminium chloride. If 203 grams of AlCl3 was produced,
Percentage yield = 203/286.64 x 100%
= 70.82%
The percentage of the reaction is 70.82%