A solution is prepared by dissolving 98.6 g of NaCl in enough water to form 875 ml of solution. The mass % of the solution if the density of the solution is 1.06 is 10.631 %.
Solution is the resultant of mixture of solute and solvent.
Number of moles of NaCl = mass of NaCl / molecular weight of NaCl
n = 98.6 / 58.5 = 1.685 moles.
mass of solution = 875 x 1.06 = 927.5 g
mass of solvent = 927.5 - 98.6 = 828.9 g or 0.8289 kg
molarity = 1.685 / 0.8289 = 2.033M
Mass % = 98.65 /927.5 = 10.631 %
Thus, the mass % of the solution for the given density of the solution is 10.631 %.
Learn more about solution.
https://brainly.com/question/7932885
#SPJ2