Respuesta :
[tex]\bf
\begin{cases}
y=25+30x\impliedby revenue\\\\
y=5x^2-10\impliedby cost
\end{cases}
\\\\\\
revenue=cost\impliedby \textit{break-even point, neither profit or loss}\qquad thus
\\\\\\
25+30x=5x^2-10\impliedby \textit{solve for "x"}[/tex]
Answer:
h = 7
Step-by-step explanation:
[tex]25 + 30x = 5x^2 - 10\\= 5x^2-30x-35\\= 5(x^2-6x-7)\\= 5((x+1)(x-7))\\\\so...\\x = -1\\x = 7[/tex]
And we want the positive one.