Question

A cylindrical swimming pool has a diameter of 16 feet and a height of 4 feet. About how many gallons of water can the pool contain? Round your answer to the nearest whole number. (1 ft³ ≈ 7.5 gal)
To the nearest whole number, the pool can hold ______ gallons of water.

Answer 1

Answer: 6029 gal

Step-by-step explanation:

The volume of cylinder is given by :-

$\text{Volume}=\pi r^2h$

Given : Diameter of cylindrical pool = 16 feet

Radius of cylindrical pool =$\frac{16}{2}=8\ ft$

Height of cylindrical pool = 4 feet

Now, The volume of cylindrical pool is given by :-

$\text{Volume}=\pi (8)^2(4)\\\\\Rightarrow\ \text{Volume}=3.14(64)(4)\\\Rightarrow\ \text{Volume}=803.84\ ft^3$

It is given that $1\ ft^3=7.5\ gal$

Therefore, The amount of water can the pool contain = $7.5\times803.84\ gal=6028.8\ gal\approx6029\ gal$