Respuesta :
[F] = [M]*[L]\[T]\[T]
F unit of force
M unit of mass
L unit of length
T unit of time
F unit of force
M unit of mass
L unit of length
T unit of time
Explanation:
We need to calculate the equations is dimensionally homogeneous.
We know that,
Unit of force is Newton.
[tex]1 N = kg-m/s^2[/tex]
Unit of mass is kg.
Unit of acceleration is m/s².
Unit of velocity is m/s.
Unit of radius is m.
Unit of time is sec.
(a). Given that,
[tex]F = ma[/tex]
Put the unit of all elements
[tex]N=kg-m/s^2[/tex]
[tex]Kg-m/s^2=kg-m/s^2[/tex]
Here, [tex]N = kg-m/s^2[/tex]
This equations is dimensionally homogeneous.
(b). Given that,
[tex]F=\dfrac{mv^2}{r}[/tex]
Put the unit in the formula
[tex]N=\dfrac{kg-m^2/s^2}{m}[/tex]
[tex]kg-m/s^2=kg-m/s^2[/tex]
This equations is dimensionally homogeneous.
(c). Given that,
[tex]F(t_{2}-t_{1})=m(v_{2}-v_{1})[/tex]
Put the unit in the formula
[tex]N-sec=kg-m/s[/tex]
[tex]kg-m/s^2\times sec=kg-m/s[/tex]
[tex]kg-m/s=kg-m/s[/tex]
This equations is dimensionally homogeneous.
(d). Given that,
[tex]F = mv[/tex]
Put the unit in the formula
[tex]N=kg-m/s[/tex]
[tex]kg-m/s^2=kg-m/s[/tex]
This equations is not dimensionally homogeneous.
(e). Given that,
[tex]F=\dfrac{m(v_{2}-v_{1})}{t_{2}-t_{1}}[/tex]
Put the unit in the formula
[tex]N=\dfrac{kg-m/s}{s}[/tex]
[tex]kg-m/s^2=kg-m/s^2[/tex]
This equations is dimensionally homogeneous.
Hence, This is required solution.