Question

Uri asked six friends how many different foreign countries they’d been to. He recorded 0, 1, 1, 2, 5, and 9 countries visited. What is the mean absolute deviation of countries visited? Round to the nearest tenth, if needed.

Answer 1

Answer:  there is mean absolute deviation of countries is 2.7 countries

Step-by-step explanation:

since we have given that

0, 1, 1, 2, 5, and 9 countries visited.

so, Mean of all countries visited is given by

$\sum x=\frac{0+1+1+2+5+9}{6}=3$

We have to calculate the mean absolute deviation of countries visited.

So, we know the formula:

$Mean\ deviation=\sum\mid x_i-\bar{x}\mid\\\\\frac{(0-3\mid+(1-3)+(1-3)+(2-3)+(5-3)+(9-3)}{6}\\\\=\frac{\mid-3-2-2-1+2+6\mid}{6}\\\\=\frac{16}{6}=2.7\ countries$

Hence, there is mean absolute deviation of countries is 2.7 countries.

Answer 2

Answer:

2.7 countries

Step-by-step explanation:

I did the test