a rock is thrown straight up with an initial velocity of 17.6 m/s. what time interval elapses between the rock's being thrown and its return to the original launch point? (acceleration due to gravity is 9.80 m/s2.)

Respuesta :

It takes 4 seconds for the rock to return to its original launch location after being hurled.

What is the formula for acceleration?

The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t).

The amount of time an object spends in the air after taking off is known as its time of flight.

The mathematical formula for time of flight is T = 2Usin(theta)/g, where U is the beginning velocity of the object, which is equal to 19.6m/s.

angle theta = 90° between the item being launched and the ground (since the body is thrown vertically upward)

g = 9.8 m/s2 is the acceleration caused by gravity.

When these values are used in the formula above, we get;

T = 2(19.6)sin90°/9.8

T = 2(19.6)(1)/9.8

T = 4seconds

As a result, it takes 4 seconds for the rock to return to its original launch location after being hurled.

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