Respuesta :
start by defining your variables
let x be the mass of a single mango in gm
let y be the mass of a single orange in gm
now, write the question as a system of equations
3 mango and 2 orange have a mass of 200 gm
3x +2y = 200
4 mango and 4 orange have a mass of 300 gm
4x +4y = 300
now you have a system of equations
3x+2y =200
4x+4y =300
solve for x and y
let x be the mass of a single mango in gm
let y be the mass of a single orange in gm
now, write the question as a system of equations
3 mango and 2 orange have a mass of 200 gm
3x +2y = 200
4 mango and 4 orange have a mass of 300 gm
4x +4y = 300
now you have a system of equations
3x+2y =200
4x+4y =300
solve for x and y
So, make two equations.
3m+2o=200
4m+4o=300
If you multiply the first equation by 2, you get 6m+4o=400.
You can take away the second equation from this so that you have
2m=100.
Therefore, m=50.
Substitute this into one of the first equations, I'm going to use the first one.
3(50)+2o=200
150+2o=200
2o=50
o=25
And finally, check by substituting into the second equation.
4(50)+4(25)=300
200+100=300
Hope this helps :)
3m+2o=200
4m+4o=300
If you multiply the first equation by 2, you get 6m+4o=400.
You can take away the second equation from this so that you have
2m=100.
Therefore, m=50.
Substitute this into one of the first equations, I'm going to use the first one.
3(50)+2o=200
150+2o=200
2o=50
o=25
And finally, check by substituting into the second equation.
4(50)+4(25)=300
200+100=300
Hope this helps :)
