Respuesta :
1/2×4=4/8
1/8=1/8
1/4×2=2/8
so 4/8+2/8=6/8
and 6/8+1/8=7/8
so 7/8 ribbons will be collected
1/8=1/8
1/4×2=2/8
so 4/8+2/8=6/8
and 6/8+1/8=7/8
so 7/8 ribbons will be collected
Question
During a bike challenge, riders have to collect various colored ribbons. Each 1/2 mile they collect a red ribbon, each 1/8 mile they collect a green ribbon, and each 1/4 mile they collect a blue ribbon. Which colors of ribbons will be collected at the 3/4 mile marker?
Answer:
A green and a blue ribbon will be collected at the [tex]\frac{3}{4}[/tex] mile marker.
Step-by-step explanation:
Topic: Factors and Multiples
To solve this, we'll write out the first few multiples of the distances where the collection of ribbons occurs:
Given that each [tex]\frac{1}{2}[/tex] mile they collect a red ribbon; The multiples for the Red Ribbon are as follows (by adding [tex]\frac{1}{2}[/tex] at each progression):
Red: [tex]\frac{1}{2} -> {1}{} -> \frac{3}{2} -> {2}{} -> \frac{5}{2}[/tex]
Given that each [tex]\frac{1}{8}[/tex] mile they collect a green ribbon; The multiples for the Green Ribbon are as follows (by adding [tex]\frac{1}{8}[/tex] at each progression):
Green: [tex]\frac{1}{8} -> \frac{1}{4} -> \frac{3}{8} -> \frac{1}{2} -> \frac{5}{8} -> \frac{3}{4} -> \frac{7}{8} -> {1}[/tex]
Given that each [tex]\frac{1}{4}[/tex] mile they collect a blue ribbon; The multiples for the Blue Ribbon are as follows (by adding [tex]\frac{1}{4}[/tex] at each progression):
Blue: [tex]\frac{1}{4} -> \frac{1}{2} -> \frac{3}{4} -> {1}[/tex]
Since , [tex]\frac{3}{4}[/tex] is a multiple of both [tex]\frac{1}{8} and \frac{1}{4}[/tex] , then a green and a blue ribbon will be collected at the [tex]\frac{3}{4}[/tex] mile marker.