Question

a certain spring compressed 0.20 m has 10 j of elastic potential energy. the spring is then cut into two halves and one of the halves is compressed by 0.20 m. how much potential energy is stored in the compressed half of the spring?

Answer 1

When the spring is then cut into two halves and one of the halves is compressed by 0.20 m, the potential energy in the spring is 10 J.

What is the spring constant of the spring?

The spring constant of the spring is the energy stored in the spring due to its elasticity.

E = ¹/₂kx²

where;

• k is the spring constant
• x is the extension of the spring

k = 2E / x²

k = ( 2 x 10 J ) / ( 0.2 m )

k = 500 N/m

When the spring is then cut into two halves and one of the halves is compressed by 0.20 m, the potential energy in the spring is calculated as;

E =  ¹/₂kx²

E =  ¹/₂(500)(0.2)²

E = 10 J

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