Respuesta :
the answers to the question would be number 2, number 3, and number 5
The correct statements are ,
- The domain is all real numbers.
- The function is negative over (–6, –2).
- The axis of symmetry is x = –4. .
Given that,
Function f(x) = (x + 6)(x + 2) .
We have to find,
The vertex, axis of symmetry, domain for the given function f(x).
- The vertex represents the lowest point on the graph or the minimum value of the quadratic function.
Which is x = -6 for the function f(x).
So, The vertex is the minimum value x = -6.
- The axis of symmetry is the vertical line that goes through the vertex of a parabola so the left and right sides of the parabola are symmetric.
Axis of symmetry = [tex]\frac{-b}{2a}[/tex]
So, f(x) = (x + 6)(x + 2) = [tex]x^{2} +8x +12[/tex]
Then, Axis of symmetry = [tex]\frac{-8}{2(1)}[/tex] = -4.
- The domain of a quadratic function f(x) is the set of x -values for which the function is defined.
The domain for f(x) = (x + 6)(x + 2) is -6 and -2 which are all real number.
- A function is called monotonically increasing (also increasing or non-decreasing).
The function is increasing over (–∞, –6) for function f(x) = (x + 6)(x + 2) .
- The y-value decreases as the x-value increases: For a function y = f(x): when [tex]x_1[/tex] < [tex]x_2[/tex] then, The function is negative over (–6, –2).
For more information about Quadratic equation click the link given below.
https://brainly.com/question/24065247