Question

a force of 500 n is required to hold a spring stretched 50 cm beyond its natural length. how much work is done in stretching the spring from its natural length to 90 cm beyond its natural length?

Answer 1

2.25 joules work is done in stretching the spring from its natural length to 90 cm beyond its natural length.

How can  determine a spring's natural length?

The spring's length without any connected mass is its natural length. Assuming the spring abides with Hooke's law The spring produces a force Fs=kL if its length is altered by an amount L from its normal length, where k is a positive quantity known as the spring constant.

distance moved = 90 cm = 0 .50 m

F = 500 N =5.00 KN

Work Done = FS = 5.00 KN * 0 .50 m

=  2.5K Joules

in stretching the spring from its natural length to 90 cm beyond its natural length is

2.5 * 0.90

2.25 joules

2.25 joules work is done in stretching the spring from its natural length to 90 cm beyond its natural length

To learn more about spring's length refer to:

https://brainly.com/question/28615861

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