100 POINTS TO RIGHT AWNSER!!!!
A compound inequality is graphed, and its graph consists of all real numbers. Which open sentence could have resulted in this solution set?



A)r > 5 or r > –1


B)r > 5 or r < –1


C)r < 5 or r < –1


D)r < 5 or r > –1

Respuesta :

lukyo
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The answer is option D)  r < 5  or  r > – 1.

I'm going to graph each inequality below on a number line.


A)  r > 5  or  r > – 1.

[tex]\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r>5~~or~~r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}[/tex]

The result is found just by joining those two intervals together. Actually that compound inequality only implies

r > – 1

which does not represent all real numbers.

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B)  r > 5  or  r < – 1.

[tex]\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r<-1}&\qquad\mathsf{\overset{~~~*****}{\textsf{|||}}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\textsf{|||}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r>5~~or~~r<-1}&\qquad\mathsf{\overset{~~~*****}{\textsf{|||}}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}[/tex]

Numbers between – 1  and  5 (including them) are not included in the union, so you don't have all real numbers represented there either.

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C)  r < 5  or  r < – 1.

[tex]\large\begin{array}{cl} \mathsf{r<5}&\qquad\mathsf{\overset{~~~********************}{\textsf{|||}\!\!\!\underset{-1}{\bullet}\!\!\!\textsf{|||||}}\!\!\underset{5}{\circ}\!\!\textsf{|||}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r<-1}&\qquad\mathsf{\overset{~~~*****}{\textsf{|||}}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\textsf{|||}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r<5~~or~~r<-1}&\qquad\mathsf{\overset{~~~********************}{\textsf{|||}\!\!\!\underset{-1}{\bullet}\!\!\!\textsf{|||||}}\!\!\underset{5}{\circ}\!\!\textsf{|||}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}[/tex]

Numbers that are greater or equal to 5 are not in the union. So it does not represent all real numbers.

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D)  r < 5  or  r > – 1.

[tex]\large\begin{array}{cl} \mathsf{r<5}&\qquad\mathsf{\overset{~~~********************}{\textsf{|||}\!\!\!\underset{-1}{\bullet}\!\!\!\textsf{|||||}}\!\!\underset{5}{\circ}\!\!\textsf{|||}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r<5~~or~~r>-1}&\qquad\mathsf{\overset{~~~**************************~~~}{\textsf{|||}\!\!\!\underset{-1}{\bullet}\!\!\!\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}[/tex]

Now all real numbers are included in the union. So this is the right choice.


Answer:  option D)  r < 5  or  r > – 1.


I hope this helps. =)

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