in maize (corn) plants, a dominant allele i inhibits kernel color, while the recessive allele i permits color when homozygous. at a different locus, the dominant allele b causes blue kernel color, while the homozygous recessive genotype bb causes red kernels. if plants heterozygous at both loci are crossed, what will be the phenotypic ratio of the offspring?

The dominant allele P is accountable for the crimson kernel colour, and the recessive genotype pp is liable for the crimson kernel colour. The recessive allele is p the phenotypic ratio is 9:3:3:1.

I is the dominant allele that inhibits the kernel colour, and that i is the recessive allele that lets in the kernel colour. The genotype of the dad and mom heterozygous for each loci could be IiPp. Punnet rectangular and the genotype of the offspring producedThe gametes produced via way of means of the offspring are IP, Ip, iP, and ip.

The offspring with genotype IIPP, IIPp, IiPP, IiPp, IIPp, IiPP, IIpp, IiPp, Iipp, IiPp, Iipp, and IiPp don't have any coloured kernels. It is because of the presence of dominant allele I in every of those offspring that inhibits kernel colour.

Phenotype ratios of the offspringOut of the 16 feasible genotypes, the dominant allele I masks the pp locus's effect, main to the formation of the colorless kernel for 3 offspring (pp).

Nine offspring (IP) can have white kernel. The crimson kernels are fashioned in 3 offspring (iiP), and the crimson kernel is advanced in a single offspring (iipp). Thus, the phenotypic ratio of the heterozygous crossing of the corn plant is 9:3:3:1.