Jonathan has 7 hours to finish three jobs. If the first job takes him 2 3/4 hours and the second joob takes him 1 5/6 hours, how much time does he have to complete the third job?
Answer with supporting work please:
this is a sum problem first you add the two known (2 3/4 + 1 5/6) =4 7/12 hours for these both jobs after you subtract this number from 7 2 5/12 is the answer hope this helped
