The sampling distribution of proportion have center equal to population proportion.
As per the details share in the above question are as follow,
The details are as follow,
Only if: Is the proportion sampling distribution regularly distributed.
[tex]\mathrm{np} > 5 \text { and } \mathrm{n}(1-\mathrm{p}) > 5[/tex]
The survey proportion's anticipated value is [tex]\mathrm{E}(\hat{\mathrm{p}})=\mathrm{p}[/tex].
As a result, the center of the proportional sampling distribution is equal to the population percentage.
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