Question

Find the solution to the quadratic equation 4y squared +26y+30=0

Answer 1

4y² + 26y + 30 = 0
a = 4
b = 26
c = 30

y = [-26 +/- √(26)² - 4(4)(30)] / [2(4)]
y = [-26 +/- √676 - 480] / [8]
y = [-26 +/- √196] / [8]
y = [-26 +/- 14] / [8]

⇒ y = [-26 + 14] / [8]
y = [12] / [8]
y = 1.5

⇒y = [-26 - 14] / [8] 
y = [-40] / [8]
y = -5