Question

place the steps involved in the reaction between a carboxylic acid and an amine in the presence of dcc in the correct order, starting with the first step at the top of the list. (not all steps are represented here.)

Answer 1

Top of the list is the first action involved in between a carboxylic acid with an amine, is:

• The COOH group assaults the DCC's core C.
• A neutral intermediate is produced via proton transfer.
• The carbonyl carbon atom is attacked by the amine, and
• dicyclohexylurea is destroyed.

An amine can be used to replace a carboxylic acid during nucleophilic substitution to generate a favorable leaving group, which can then be replaced by an amide to form the matching amide. Below is a breakdown of the reaction steps: Acid deprotonation is the first step. Step 2: The carboxylate launches a nucleophilic assault.

Because amines are basic and frequently convert carboxylic acids to their very unreactive carboxylates, it is challenging to convert a carboxylic acid directly to an amide. A good leaving group is created in this reaction by the addition of the carboxylic acid to the DCC molecule, which can then be replaced by an amine during nucleophilic substitution. In the synthesis of peptides, an important step is DCC-induced coupling to generate an amide bond.

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