Respuesta :
As per the rate of change, the brass rod expand 5.927 x 10²mm than the invar rod.
The term rate of change defines the ratio between the change in one quantity to the change in another quantity
Here we know that Two students each build a piece of scientific equipment that uses a 855-mm-long metal rod.
And we need to find how much the the brass rod expand than the invar rod.
As we know that the process of thermal expansion occurs when objects are heated as well as expanded.
So, in case the temperature of an object changes through Δt, as well as length changes through and the length's fractional changes ΔL are effective to the temperature's change ΔT.
Here for the Brass, plug the values of brass, L, T into equation in order to
get L[brass]
L[brass] = (1.9x 10-5°C-1)(655 mm)(5°C)
= 0.06222mm
Similarly, plug the values of L, T, A[invar] into equation in order to get L[invar]
L[invar] = (0.09×10-5°C-¹)(655 mm)(5°C)
=0.00295 mm
Then the calculation depicted the brass changes through a larger value of invar and the difference is
L = L[brass] - L[invar]
L = 0.06222mm-0.00295mm
L = 0.05927 mm
L = 5.927 x 10²mm
To know more about Rate of change here.
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