The work required to pump all the water over the top of the tank can be calculated using the following definite integral:
W = ∫0^2 (1000 kg/m³)(9.8 m/s²)(5 m)(x) dx
This integral represents the work required to pump the water over the top of the tank. The integral is calculated over the length of the tank, which is 2 meters. The density of the water is 1000 kg/m³, and the acceleration due to gravity is 9.8 m/s². The height of the water is 5 meters.
The variable x is used to represent the distance along the length of the tank. This integral can then be evaluated to find the total work required to pump the water over the top of the tank.
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