Question

A pair of 0.00300 mm wide slits are separated by 0.115 mm. A flat screen lies 1.88 m from the pair of slits. Light having wavelengths of either 693 nm (red) or 502 nm (green) is incident on the slits at any given time. a) Which wavelength will give the wider single-slit diffraction maxima? How much wider in cm or m is the central diffraction maximum for that color of light than the other? You cannot use the small angle approximation in this case. b) How many double-slit interference maxima can be found within 5.00 cm on either side of the pattern's center for each color? Do not count the central maximum. You may use the small angle approximation for this part of the problem, and this will be a whole number!

Answer 1

The equation d(sin)=m is used to determine a diffraction maxima. The equation d(sin)=(m+12) is used to determine a diffraction pattern's minima. where m is an integer.

Every continuous function in a closed domain has a maximum and a minimum Value, which can be found inside or outside the domain. The maxima for the various wavelengths will occur at somewhat different times under white light, which contains all the wavelengths in the visible spectrum. When two crests or two troughs of two distinct waves meet and reinforce one another, this is known as an interference maximum. On the other hand, a minima in interference is a place where a crest and a trough meet and balance each other out.

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