Question

A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and vertical components of the skier's displacement?

Answer 1

Opposite from the angle is 134.7905

Adjacent to the angle is 192.5007

Answer 2

Explanation:

It is given that,

Height of the mountain, h = 235 m

A skier descends a mountain at an angle of 35º to the horizontal, $\theta=35^{\circ}$

We need to find the horizontal and vertical components of the skier's displacement.

Horizontal component, $x=h\ cos\theta$                                    

$x=235\ cos(35)=192.5\ m$          

Vertical component, $y=h\ sin\theta$                                    

$y=235\ sin(35)=134.79\ m$          

Hence, this is the required solution.