An object moves at a constant speed in a circular path of radius r at a rate of 1 revolution per second. What is its acceleration?
A. 0
B. 2π2r
C. 2π2r2
D. 4π2

Respuesta :

The acceleration of the object moving at a constant speed of 1 revolution per second is 4π²r.

We know that, a body in circular motion possesses centripetal acceleration.

The formula for force according to Newton's second law is F = m * a

The formula for centripetal force is F = (m*v2)/r

By combining both the equations, we can write a = v²/r ---(1)

Given that, constant speed is at the rate of 1 revolution per second.

1 revolution is nothing but the perimeter of the circle which is known as 2π*r.

As the object covers a distance of 2π*r in 1 revolution, its speed is 2π*r m/sec.

From equation (1), Acceleration a = (2π*r)²/r = 4π²r

Thus, the acceleration is 4π²r.

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