Question

A 8.0 kg block slides 2.0 m along a frictionless incline (measured along the incline L as shown). The incline makes an angle = 60° to the horizontal. Determine work done by normal force, and work done by gravitational force. O Work done by normal force is about 0 N, and work done by gravitational force is about 75.1J O Work done by normal force is about 78.4 N, and work done by gravitational force is about 156.8 J. O Work done by normal force is about 0 N, and work done by gravitational force is about 156.8 J.O Work done by normal force is about 0 N, and work done by gravitational force is about 135.8 J. O Work done by normal force is about 78.4 N, and work done by gravitational force is about 135.8 J.

Answer 1

Work done by the normal force is about 78.4 N, and work done by the gravitational force is about 135.8 J. Option D.

Calculation:

M = 8kg

O =60

work done by the gravity

Wa= $\int\limits^_ {} \,$ FG. ds = $\int\limits^_ {} \,$FG. ds cos (90-60)

Wa = $\int\limits^2_0 {} \,$ mg cos30. ds

Wa = $\int\limits^2_0 {} \,$8x9.8x0.866.ds

Wa = 135.788 N.m ≈ 135.8 J

Work done by the normal force

WN= $\int\limits^_ {} \,$N.ds = $\int\limits^_ {} \,$N.ds cos90°.

The normal force is the force exerted by a surface to prevent solid objects from passing through each other. The normal force is the contact force. If two surfaces are not in contact, they cannot exert a force perpendicular to each other. The normal force is defined as the force that a surface exerts on another body. When this object is at rest it means that the net force acting on the object is zero.

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