For each of the compounds below, explain why they do not have the same value for their standard heat of vaporization.
1. Propane and propanone
2. Propanone and 1-propanol

Respuesta :

All the molecules have Van der Waals forces between them but propanol has the addition of having hydrogen bonding, which is barely stronger.

The improved forces between molecules capability that extra energy is required to destroy apart the molecules and therefore the substance has a greater boiling point.

Why do heavier compounds have greater boiling points?

Large molecules have extra electrons and nuclei that create van der Waals pleasing forces, so their compounds usually have greater boiling factors than similar compounds made up of smaller molecules.

Because 1-propanol has its hydroxyl to one side, the hydrogen bonds it forms can pack collectively greater densely than with 2-propanol, requiring extra kinetic electricity (temperature) to wreck them apart, which interprets to a greater boiling point

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